Advanced Higher
Differentiation
L.I. To look at calculating the second derivative of parametric equations and to look at related rates and their application of the chain rule.
S.C. I know the formula for calculating the second derivative of a function defined by parametric equations.
I understand that related rates are an application of the chain rule
I can use the fact that they are an application of the chain rule to calculate the rate asked for.
2(1)
Pythagoras' Theorem
L.I. To be able to choose the correct format of Pythagoras to calculate the hypotenuse or one of the shorter sides in a question with context
S.C. I can identify a right-angled triangle in the context of the question
I can identify which side of the triangle the question is asking me to calculate
I can use the appropriate format of Pythagoras' Theorem to calculate the missing side
Wednesday, 29 October 2014
Tuesday, 28 October 2014
Tuesday the 28th of October
National 5
Volume of pyramids, cones and spheres
L.I. To get practice in at using the formulas for volume given on the formula sheet and to start to think about communication of their answers
S.C. I can use the formula for volume of a pyramid, cone and sphere to calculate the volume of a given shape.
I can use this answer to communicate the answer to the question being asked.
Advanced Higher
Differentiation
L.I. To use paramettric differentiation to calculate the equation of a tangent at a point given a parametric function.
S.C. I can use parametric differentiation to find dy/dx by finding dy/dt and dx/dt
I can then find the gradient at the given coordinates and find the equation of the tangent
Volume of pyramids, cones and spheres
L.I. To get practice in at using the formulas for volume given on the formula sheet and to start to think about communication of their answers
S.C. I can use the formula for volume of a pyramid, cone and sphere to calculate the volume of a given shape.
I can use this answer to communicate the answer to the question being asked.
Advanced Higher
Differentiation
L.I. To use paramettric differentiation to calculate the equation of a tangent at a point given a parametric function.
S.C. I can use parametric differentiation to find dy/dx by finding dy/dt and dx/dt
I can then find the gradient at the given coordinates and find the equation of the tangent
Monday, 27 October 2014
Monday the 27th of October
2(1)
Pythagoras' Theorem
L.I. To be able to choose the correct format of Pythagoras to calculate the hypotenuse or one of the shorter sides
S.C. I can identify which side of the triangle the question is asking me to calculate
I can use the appropriate format of Pythagoras' Theorem to calculate the missing side
Advanced Higher
Differentiation
L.I. To introduce the technique of parametric differentiation.
S.C. I can differentiate x and y in terms of t (or other variable)
I can find (dy/dt)/(dx/dt) and simplify
Pythagoras' Theorem
L.I. To be able to choose the correct format of Pythagoras to calculate the hypotenuse or one of the shorter sides
S.C. I can identify which side of the triangle the question is asking me to calculate
I can use the appropriate format of Pythagoras' Theorem to calculate the missing side
Advanced Higher
Differentiation
L.I. To introduce the technique of parametric differentiation.
S.C. I can differentiate x and y in terms of t (or other variable)
I can find (dy/dt)/(dx/dt) and simplify
Friday, 24 October 2014
Friday the 24th of October
2(1)
Pythagoras' Theorem
L.I. To be able to choose the correct format of Pythagoras to calculate the hypotenuse or one of the shorter sides
S.C. I can identify which side of the triangle the question is asking me to calculate
I can use the appropriate format of Pythagoras' Theorem to calculate the missing side
National 5
Volume of solids
L.I. To calculate the volume of prisms and a cylinder in particular.
S.C. I can identify a prism
I can calculate the volume of a prism by multiplying the area of it's face by it's height.
I can calculate the volume of a cylinder by using the formula V = pi r^2 h
Pythagoras' Theorem
L.I. To be able to choose the correct format of Pythagoras to calculate the hypotenuse or one of the shorter sides
S.C. I can identify which side of the triangle the question is asking me to calculate
I can use the appropriate format of Pythagoras' Theorem to calculate the missing side
National 5
Volume of solids
L.I. To calculate the volume of prisms and a cylinder in particular.
S.C. I can identify a prism
I can calculate the volume of a prism by multiplying the area of it's face by it's height.
I can calculate the volume of a cylinder by using the formula V = pi r^2 h
Wednesday, 22 October 2014
Wednesday the 22nd of October
Advanced Higher
Differentiation
L.I. To find the second derivative using implicit differentiation and to use logarithmic differentiation when differentiating expressions with roots or powers of x
S.C. I can differentiate an implicit equation to find dy/dx
I can differentiate an implicit equation to find the second derivative
I can use logs to make a function easier to differentiate
I can use logarithmic differentiation to differentiate expressions
Differentiation
L.I. To find the second derivative using implicit differentiation and to use logarithmic differentiation when differentiating expressions with roots or powers of x
S.C. I can differentiate an implicit equation to find dy/dx
I can differentiate an implicit equation to find the second derivative
I can use logs to make a function easier to differentiate
I can use logarithmic differentiation to differentiate expressions
Tuesday, 21 October 2014
Tuesday the 21st of October
National 5
Angles in a semi-circle and tangents
L.I. To review angles in a semi-circle and to look at tangents to a circle
S.C. I understand that triangle in a semi-circle is right angled if it is made from a diameter and two lines joining from opposite ends of the diameter.
I can use my knowledge of angles in a triangle to fill in missing angles as needed.
I can use my knowledge of Pythagoras to calculate missing lengths.
I understand what a tangent is and how it connects to the circle.
I can use my knowledge of angles in a triangle to fill in missing angles as needed.
I can use my knowledge of Pythagoras to calculate missing lengths.
Angles in a semi-circle and tangents
L.I. To review angles in a semi-circle and to look at tangents to a circle
S.C. I understand that triangle in a semi-circle is right angled if it is made from a diameter and two lines joining from opposite ends of the diameter.
I can use my knowledge of angles in a triangle to fill in missing angles as needed.
I can use my knowledge of Pythagoras to calculate missing lengths.
I understand what a tangent is and how it connects to the circle.
I can use my knowledge of angles in a triangle to fill in missing angles as needed.
I can use my knowledge of Pythagoras to calculate missing lengths.
Advanced Higher
Differentiation
L.I. To use implicit differentiation to calculate the equation of the tangent to a curve.
S.C. I can differentiate an expression written implicitly
I can use this to find dy/dx
I know that dy/dx found at a certain point will give me the gradient of the tangent to y
I can find the equation of the tangent asked for.
Monday, 20 October 2014
Monday the 20th of October
Advanced Higher
Differentiation unit 2
L.I. To differentiate expressions containing inverse trigonometric functions.
S.C. I know the differentiated expressions for the 3 main inverse trig functions
I can apply this knowledge and use the rules from unit 1 to differentiate expressions containing inverse trig functions.
Advanced Higher
Differentiation
L.I. To introduce the idea of implicit differentiation
S.C. I can differentiate an expression containing both x and y terms
I can find dy/dx once I have differentiated
Differentiation unit 2
L.I. To differentiate expressions containing inverse trigonometric functions.
S.C. I know the differentiated expressions for the 3 main inverse trig functions
I can apply this knowledge and use the rules from unit 1 to differentiate expressions containing inverse trig functions.
Advanced Higher
Differentiation
L.I. To introduce the idea of implicit differentiation
S.C. I can differentiate an expression containing both x and y terms
I can find dy/dx once I have differentiated
Friday, 10 October 2014
Friday the 10th of October
2(1)
Pythagoras' Theorem
L.I. To use Pythagoras' Theorem to calculate the short side of a right angled triangle
S.C. I understand how the formula for finding the hypotenuse can be changed to find the short side
I can find the short side of a right-angled triangle using this formula
I can check my answer is smaller than the hypotenuse
I can do all of this in a real life problem.
National 5
Angles in a circle and a semi-circle
L.I. To continue yesterdays ideas of triangles in a circle and using Pythagoras and introducing the idea of angles in a semi-circle and using trigonometry and Pythagoras to solve these questions.
S.C. I understand that two radii connected by a chord create an isosceles triangle
I can use Pythagoras' Theorem to find missing sides
I understand that a two chords touching the diameter at opposite ends and meeting at their other end creates a right-angled triangle inside the semi-circle
I can use Pythagoras' and Trigonometry to answer questions using this fact
Pythagoras' Theorem
L.I. To use Pythagoras' Theorem to calculate the short side of a right angled triangle
S.C. I understand how the formula for finding the hypotenuse can be changed to find the short side
I can find the short side of a right-angled triangle using this formula
I can check my answer is smaller than the hypotenuse
I can do all of this in a real life problem.
National 5
Angles in a circle and a semi-circle
L.I. To continue yesterdays ideas of triangles in a circle and using Pythagoras and introducing the idea of angles in a semi-circle and using trigonometry and Pythagoras to solve these questions.
S.C. I understand that two radii connected by a chord create an isosceles triangle
I can use Pythagoras' Theorem to find missing sides
I understand that a two chords touching the diameter at opposite ends and meeting at their other end creates a right-angled triangle inside the semi-circle
I can use Pythagoras' and Trigonometry to answer questions using this fact
Thursday, 9 October 2014
Thursday the 9th of October
2(1)
L.I. To use Pythagoras' Theorem in "real life" problems
S.C. I can spot the right angled triangle in the question
I can use Pythagoras' Theorem to calculate the hypotenuse
I can use the answer to answer the question asked
L.I. To use Pythagoras' Theorem in "real life" problems
S.C. I can spot the right angled triangle in the question
I can use Pythagoras' Theorem to calculate the hypotenuse
I can use the answer to answer the question asked
National 5
Circles
L.I. To look at how a triangle made up of two radii from a circle and a chord create an isosceles triangle and how we can use that fact to calculate different parts of the circle
S.C. I can see that a triangle made of 2 radii and a chord makes an isosceles triangle
I can find the angles missing in a triangle
I can use Pythagoras' Theorem to find missing sides.
Wednesday, 8 October 2014
Wednesday the 8th of October
2(1)
Pythagoras' Theorem
L.I. To calculate the length of the hypotenuse in a right angled triangle
S.C. I can identify the hypotenuse of a right angled triangle
I can start Pythagoras' Theorem by substituting in the values and squaring the terms
I can finish Pythagoras's theorem by adding the two squares together and then finding the square root
Pythagoras' Theorem
L.I. To calculate the length of the hypotenuse in a right angled triangle
S.C. I can identify the hypotenuse of a right angled triangle
I can start Pythagoras' Theorem by substituting in the values and squaring the terms
I can finish Pythagoras's theorem by adding the two squares together and then finding the square root
Tuesday, 7 October 2014
Tuesday the 7th of October
National 5
Circle
L.I. to use the fraction of the circle connection to calculate the area of a sector of a circle
S.C. I understand what a sector of a circle is
I can use the angle at the centre to find the fraction of the circle and use it in my formula
I can calculate the area of a sector of a circle
L.I. to use the fraction of the circle connection to calculate the angle of the sector
S.C. I can use the circumference and arc length to calculate the fraction of the circle
I can use the area of a circle and the area of a sector to calculate the fraction of the circle
I can use the fraction of a circle to calculate the angle in the sector between the two radii
Circle
L.I. to use the fraction of the circle connection to calculate the area of a sector of a circle
S.C. I understand what a sector of a circle is
I can use the angle at the centre to find the fraction of the circle and use it in my formula
I can calculate the area of a sector of a circle
L.I. to use the fraction of the circle connection to calculate the angle of the sector
S.C. I can use the circumference and arc length to calculate the fraction of the circle
I can use the area of a circle and the area of a sector to calculate the fraction of the circle
I can use the fraction of a circle to calculate the angle in the sector between the two radii
Friday, 3 October 2014
Friday the 3rd of October
2(1)
Factorising
L.I. To introduce the concept of factorising by the common factor method.
S.C. I can find the highest common factor of two terms
I can factorise an expression using common factors
National 5
1st period
Gradient
L.I. to determine the gradient of a straight line given two points on a cartesian diagram.
S.C. I can identify 2 points on the line
I can plug these points into the formula for calculating the gradient
I understand what is meant by the gradient and what it means when we calculate it.
2nd period
Circle
L.I. To calculate the arc length of a circle
S.C. I know the formula to calculate the circumference of a circle
I can use the fact that the angle at the centre can be used to calculate the fraction of the circle that is being used.
I can calculate the length of a major or minor arc.
Factorising
L.I. To introduce the concept of factorising by the common factor method.
S.C. I can find the highest common factor of two terms
I can factorise an expression using common factors
National 5
1st period
Gradient
L.I. to determine the gradient of a straight line given two points on a cartesian diagram.
S.C. I can identify 2 points on the line
I can plug these points into the formula for calculating the gradient
I understand what is meant by the gradient and what it means when we calculate it.
2nd period
Circle
L.I. To calculate the arc length of a circle
S.C. I know the formula to calculate the circumference of a circle
I can use the fact that the angle at the centre can be used to calculate the fraction of the circle that is being used.
I can calculate the length of a major or minor arc.
Thursday, 2 October 2014
Thursday the 2nd of October
2(1)
Factors
L.I. To look at factors of algebraic terms as well as factors of numbers and to look for highest common factors.
S.C. I can find all the factors of a number
I can find all the factors of an algebraic term
I can find the highest common factor of any two terms
National 5
Gradients
L.I. To introduce the idea of gradient and how it is calculated and to understand what it means.
S.C. I know the formula for calculating the gradient
I can identify the vertical and horizontal distances
I can calculate the gradient
I can compare the gradient of two or more slopes
I understand that the higher the gradient the steeper the slope will be.
Factors
L.I. To look at factors of algebraic terms as well as factors of numbers and to look for highest common factors.
S.C. I can find all the factors of a number
I can find all the factors of an algebraic term
I can find the highest common factor of any two terms
National 5
Gradients
L.I. To introduce the idea of gradient and how it is calculated and to understand what it means.
S.C. I know the formula for calculating the gradient
I can identify the vertical and horizontal distances
I can calculate the gradient
I can compare the gradient of two or more slopes
I understand that the higher the gradient the steeper the slope will be.
Wednesday, 1 October 2014
Wednesday the 1st of October
Advanced Higher
Functions
L.I. To get more practice at sketching rational functions and annotating them correctly
S.C. I can find the points where the graph cuts the axes
I can find any asymptotes, both vertical and non-vertical
I can find any stationary points
I can sketch the graph of the function
2(1)
Algebra
L.I. To put the three techniques together to solve equations
S.C. I can multiply out brackets
I can tidy expressions
I can solve equations
Functions
L.I. To get more practice at sketching rational functions and annotating them correctly
S.C. I can find the points where the graph cuts the axes
I can find any asymptotes, both vertical and non-vertical
I can find any stationary points
I can sketch the graph of the function
2(1)
Algebra
L.I. To put the three techniques together to solve equations
S.C. I can multiply out brackets
I can tidy expressions
I can solve equations
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