Wednesday, 25 June 2014

Wednesday the 25th of June

Advanced Higher Differentiation
L.I. To use higher derivatives to calculate the nature of a stationary point.  To use higher derivatives in the context of motion in a straight line.
S.C. I can calculate the 2nd, 3rd and 4th derivatives of a function
       I can use the 2nd derivative to find the nature of a stationary point
       I understand the connection between displacement, velocity and acceleration and can use differentiation to calculate each





 
3(3) Trigonometry
L.I. To use the inverse sin function to calculate the missing angle in right-angled triangles
S.C. I can identify the opposite and the hypotenuse of a right-angled triangle
       I can use the calculator to find the inverse sin of  a number less than 1
      I can calculate the missing angle on a right-angled triangle
 
 

Tuesday, 24 June 2014

Tuesday the 24th of June

National 5 Scientific notation
L.I. Pupils will look at writing large and small numbers in scientific notation (standard form)  They will also look at significant figures
S.C. I can write a large number using scientific notation
       I can covert a number in scientific notation back to "normal form"
       I can write a small number using scientific notation
      I can write a number to a given number of significant figures

3(3) Trigonometry
L.I. To use the sine ratio to calculate the length of the opposite side
S.C. I can see the difference between the tangent ratio and the sine ratio
       I can use the formula correctly to calculate the missing side
Advanced Higher Differentiation
L.I. To look at differentiating functions containing natural logs (ln(x))
S.C. I know that d/dx ln(x) = 1/x
       I can differentiate functions containing natural logs
 
 

Monday, 23 June 2014

Monday the 23rd of June

2(1) Patterns
L.I. To look at simple linear patterns and to calculate a formula to explain the pattern
S.C. I can identify the number the pattern is going up in each time
       I can write the formula in words
       I can write the formula in symbols

National 3 Perimeter
L.I. To calculate the length of a perimeter of an irregular shape
S.C. I can fill in missing lengths based on the information given
       I can calculate the perimeter of a shape

Advanced Higher Differentiation
L.I. Pupils will learn about more trigonometric functions and their derivatives.  Pupils will also look at differentiating exponential functions.
S.C. I can remember the definitions of cot(x) sec(x) and cosec(x)
       I can remember the derivatives of tan(x), cot(x), sec(x) and cosec(x)
       I can differentiate functions containing these expressions using the chain rule, the product rule and the quotient rule as needed
       I can differentiate functions containing the expression e^x.
 



Friday, 20 June 2014

Friday the 20th of June

2(1) Patterns
L.I. To get the pupils to look at basic number patterns to give a possible rule for the pattern and to continue the pattern.
S.C. I can create a basic rule for a number pattern stating the start and what you do to reach the next number
       I can continue a number pattern to a given number of places

National 5 Surds and indices
L.I. To consolidate the rules of indices by using them all in examples.
S.C. I can simplify expressions using all of the laws of indices
       I can express my final answer with positive indices
    

Thursday, 19 June 2014

Thursday the 19th of June

2(1) Ratio
L.I. To try further examples of ratio calculations and to continue to understand how to use proportional division
S.C. I can see how many parts I have to split something into
       I can find the single amount
       I can multiply up and find how much each part gets
 
 
3(3) Trigonometry
L.I. To calculate the size of an angle using the tanget ratio.
S.C. I can identify the opposite, adjacent and hypotenuse
       I can use the inverse button on the calculator to find the inverse tan and the angle given the opposite and adjacent
 
National 3 Measurement
L.I. To look at various polygons and to calculate their perimeter.
S.C. I understand what a shapes perimeter is
       I can fill in missing sides with my knowledge of different shapes and notations
       I can calculate the perimeter of a shape
       I can calculate a missing side if I know the other sides and the perimeter

Wednesday, 18 June 2014

Wednesday the 18th of June

Advanced Higher Differentiation
L.I. To introduce the product and quotient rule and to use these to differentiate functions.
S.C. I can use the product rule to differentiate a function
       I can use the quotient rule to differentiate a function





2(1) Ratio Calculations
L.I. To use ratios to calculate how to split an amount in a given ratio
S.C. I can see how many parts I have to split something into
       I can find the single amount
       I can multiply up and find the amount asked for in the question
 

3(3) Trigonometry
L.I. To use the tangent ratio to calculate the length of a missing side (the opposite) of a right-angled triangle
S.C. I can correctly identify and label the sides of a triangle
       I can use the tan button on my calculator to find the ratio of the angle
       I can use the formula correctly to calculate the length of the side asked for

Tuesday, 17 June 2014

Tuesday the 17th of June

National 5 Surds and indices
L.I. To find the remaining rules surroundling indices and to use them to simplify examples
S.C. I know that a^0 = 1
       I know that a^-m = 1/a^m
       I know that a^(m/n) = the nth root of a^m
       I can use these facts, along with the previous rules to simplify expressions involving indices
 
3(3) Intro to Trigonometry
L.I. To see that there is a connection between the ratio of the opposite and the adjacent sides and the angle that defines these sides
S.C. I can see the link between the vertical and the horizontal sides on a right-angled triangle and the angle
       I can use the tangent ratio to calculate the length of the opposite side
 

Advanced Higher Partial Fractions
L.I. To bring the ideas of algebraic long division and decomposing a fraction into partial fractions together to simplify improper rational functions.
S.C. I can divide an improper rational function in order to split it
       I can split the fraction into partial fractions
 



Monday, 16 June 2014

Monday the 16th of June

2(1) Ratio
L.I. To continue simplifying ratios with harder examples
S.C. I can simplify a ratio with whole numbers on each side
       I can simplify a ratio that contains fractions

National 3 Area
L.I. To continue working with the area of a rectangle, square and triangle
S.C. I can identify which of the formulae to use to calculate the area of an appropriate shape
       I can correctly use the appropriate formula
       I can state the correct units
Advanced Higher Partial Fractions
L.I. To decompose into partial fractions that contain an irreducible quadratic factor on it's denominator.
S.C. I can identify an irreducible quadratic factor
       I can seperate a fraction into it's correct parts and use the correct general form
       I can find the fraction in it's decomposed partial fractions form


 

Thursday, 12 June 2014

Friday the 13th of June

2(1) Ratio
L.I. to simplify ratios into their most simple form
S.C. I can identify the highest common factor of two or three numbers
       I can divide both sides of the ratio by that common factor
       I can write down the ratio in it's simplest form.

 
National 5 Surds and indices
L.I. To review previous knowledge of the rules associated with surds and indices
S.C. I can use the rules of surds to simplify a surd
       I can use the rules of surds to rationalise a denominator
       I can use the laws of indices to simplify an expression
 
See previous blogs for examples

Thursday the 12th of June

2(1) Ratios
L.I. To introduce the idea of a ratio, the notation that is used and the idea of the order being important
S.C. I can write a ratio using the correct notation
       I understand the use of ratio in everyday calculations

3(3) Pythagoras' Theorem
L.I. To try mixed examples of calculating the hypotenuse or short side of a right-angled triangle
S.C. I can identify if the question is asking me to find the hypotenuse or one of the short sides
       I can use the appropriate formula to calculate the missing side

National 3 Area
L.I. To look at how to calculate the area of a right-angled triangle
S.C. I can see that a right-angled triangle is half of a rectangle
       I can calculate the area of a right-angled triangle showing the appropriate working.
 

 

Wednesday, 11 June 2014

Wednesday the 11th of June

Advanced Higher Partial Fractions
L.I. To look at how to split a fraction with linear factors in its denominator into partial fractions.
S.C. I can split a fraction with distinct linear factors into partial fractions
       I can split a fraction with repeated linear factors into partial fractions




2(1) Quadrilaterals
L.I. To use all of the properties of the quadrilaterals we have looked at over the last few lessons to fill in missing lengths and missing angles.
S.C. I can identify the quadrilateral by it's properties
       I can remember the properties of the shapes we have looked at over the last few periods
       I can identify missing angles and missing lengths of different quadrilaterals based on my knowledge of that shapes properties
 
3(3) Pythagoras' Theorem
L.I. To introduce the idea of using Pythagoras' Theorem to calculate one of the two short sides on a right-angled triangle.
S.C. I can identify which side is missing from the triangle
       I understand the connection between the formula for calculating the hypotenuse and calculating the short side.
       I can calculate the short side of a right-angled triangle using Pythagoras' Theorem     



Tuesday, 10 June 2014

Tuesday the 10th of June

National 5 Surds and indices
L.I. To continue with the idea of simplifying and surds and to introduce the first three rules of indices.
S.C. I can simplify a surd into its simplest form
       I can rationalise a denominator and simply the fraction
       I can use the first rule of indices to simplify an expression
       I can use the second rule of indices to simplify an expresssion
       I can use the third rule of indices to simplify an expression


3(3) Pythagoras Theorem in context
L.I. To be able to identify a right angled triangle in context and to use Pythagoras' Theorem to calculate the length of the hypotenuse
S.C. I can identify a right angled triangle in the context of a question
       I can use Pythagoras' Theorem to identify the length of the missing side (the hypotenuse)


 
Advanced Higher Partial Fractions
L.I. To use algebraic long division to simplify improper rational functions.
S.C. I can identify a proper and improper rational function
       I can simplify an improper rational function using algebraic long division.