Monday, 8 December 2014

Monday the 8th of December

2(1)
Equation of a straight line
L.I. To find the equation of a straight line given two points, one of which is the y-intercept.
S.C. I know that y = mx + c where m is the gradient and c is the y-intercept
       I can calculate the gradient using m = (y1 - y2)/(x1 - x2)
       I can substitute into the formula y = mx + c to get the equation of the straight line

Advanced Higher
Complex Numbers
L.I. To calculate the modulus and argument of a complex number and to write it in polar form.
S.C. I can find the modulus of a complex number |z|
       I can find the principal argument of a complex number arg(z)
       I can use these to find the complex number in polar form
       I can work backwards from polar form into cartesian form.


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